Question

\(\left(4x-9\right).\left(2,5+\dfrac{-7}{3}.x\right)=0\)

Answer 1

=>4x-9=0 hoặc 5/2-7/3x=0

=>x=9/4 hoặc x=15/14

Answer 2

\(\left(4x-9\right).\left(2,5+\dfrac{-7}{3}.x\right)=0\)

\(=>\left[{}\begin{matrix}4x-9=0\\2,5+\dfrac{-7}{3}.x=0\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=\dfrac{15}{14}\end{matrix}\right.\)

Answer 3

=> \(\left(4x-9\right).\left(\dfrac{5}{2}+\dfrac{-7}{3}.x\right)=0\)

=> \(\left[{}\begin{matrix}4x-9=0\\\dfrac{5}{2}+\dfrac{-7}{3}.x=0\end{matrix}\right.=>\left[{}\begin{matrix}4x=9=>x=\dfrac{9}{4}\\\dfrac{-7}{3}.x=\dfrac{-5}{2}=>x=\dfrac{15}{14}\end{matrix}\right.\)

Answer 4

\(\left(4x-9\right).\left(2,5+\dfrac{-7}{3}x\right)=0\)

<=>\(4x-9=0\)         hoặc          \(2,5+\dfrac{-7}{3}x=0\)

<=>x=\(\dfrac{9}{4}\)                                      <=> \(-\dfrac{7}{3}x=-\dfrac{5}{2}\)

                                                     <=> \(x=\dfrac{15}{14}\)

 Vậy x\(\in\left\{\dfrac{9}{4};\dfrac{15}{14}\right\}\)