Question

\(\left(2x^2+8\right)\left(\left|x\right|-2\dfrac{1}{3}\right)=0\)

 

Answer 1

\(=>\left[{}\begin{matrix}2.x^2+8=0\\\left|x\right|-2\dfrac{1}{3}=0\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}2.x^2=0-8\\\left|x\right|=0+2\dfrac{1}{3}\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}2.x^2=-8\\\left|x\right|=\dfrac{7}{3}\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}x^2=-8:2\\\left[{}\begin{matrix}x=\dfrac{7}{3}\\x=-\dfrac{7}{3}\end{matrix}\right.\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}x\in\varnothing\\\left[{}\begin{matrix}x=\dfrac{7}{3}\\x=-\dfrac{7}{3}\end{matrix}\right.\end{matrix}\right.\)

Vậy ......

 

 

Answer 2

=>|x|-7/3=0

=>x=7/3 hoặc x=-7/3