\(\left(2\sqrt{x}+1\right)\left(\sqrt{x}-2\right)=7\) ; \(\left(x\ge0\right)\)
\(\Leftrightarrow2x-4\sqrt{x}+\sqrt{x}-2=7\)
\(\Leftrightarrow2x-3\sqrt{x}-9=0\)
\(\Leftrightarrow\left(\sqrt{x}-3\right)\left(2\sqrt{x}+3\right)=0\)
\(\Leftrightarrow\sqrt{x}-3=0\) ( vì \(2\sqrt{x}+3>0\) )
\(\Leftrightarrow\sqrt{x}=3\)
`<=>x=9`
Vậy \(S=\left\{9\right\}\)