Question

\(\left(2+3x\right)^2=9\)

Answer 1

\(\left(2+3x\right)^2=9=\left(3\right)^2=\left(-3\right)^2\)

(+) 2 +3x = 3 => 3x = 3 - 2 

=> 3 x = 1 

=> x = 1/3 

(+) 2 + 3x = - 3

=> 3x = -3 - 2 

=> 3x = -5 

=> x = -5/3 

Answer 2

\(\left(2+3x\right)^2=9=3^2=\left(-3\right)^2\)

=>2+3x=3,-3

=>3x=1,-5

=>x=1/3,-5/3