Question

làm hộ e nhé, tick nha:>

Answer 1

Bài 5: 

a) Đặt P(x)=0

\(\Leftrightarrow5x-10=0\)

\(\Leftrightarrow5x=10\)

hay x=2

b) Đặt Q(x)=0

\(\Leftrightarrow x^3-5x=0\)

\(\Leftrightarrow x\left(x-\sqrt{5}\right)\left(x+\sqrt{5}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\sqrt{5}\\x=-\sqrt{5}\end{matrix}\right.\)