Question

Làm giúp 1 bài nữa nhé!

Phân tích đa thức thành nhân tử.

3x² + 2x – 1x³ + 6x² + 11x + 6x⁴ + 2x² – 3ab + ac +b² + 2bc + c²a³ – b³ + c³ + 3abc

Answer 1

1)\(3x^2+2x-1=3x^2+3x-x-1=3x\left(x+1\right)-\left(x+1\right)=\left(3x-1\right)\left(x+1\right)\)

2)\(x^3+6x^2+11x+6=x^3+3x^2+3x^2+9x+2x+6\)

\(=x^2\left(x+3\right)+3x\left(x+3\right)+2\left(x+3\right)\)\(=\left(x^2+3x+2\right)\left(x+3\right)\)

\(=\left(x^2+2x+x+2\right)\left(x+3\right)\)\(=\left[x\left(x+2\right)+\left(x+2\right)\right]\left(x+3\right)\)

\(=\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

3)\(x^4+2x^2-3=x^4+3x^2-x^2-3=x^2\left(x^2+3\right)-\left(x^2+3\right)=\left(x^2-1\right)\left(x^3+3\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x^2+3\right)\)

4)\(ab+ac+b^2+2bc+c^2=a\left(b+c\right)+\left(b+c\right)^2=\left(b+c\right)\left(a+b+c\right)\)

5) câu này sau khi phân tích được (a-b+c)(a²+b²+c²+ab+bc-ac)