1: \(5\cdot8=4\cdot10\)
=>\(\dfrac{5}{4}=\dfrac{10}{8};\dfrac{5}{10}=\dfrac{4}{8};\dfrac{4}{5}=\dfrac{8}{10};\dfrac{10}{5}=\dfrac{8}{4}\)
2: \(\left(-2\right)\cdot6=\left(-4\right)\cdot3\)
=>\(\dfrac{-2}{-4}=\dfrac{3}{6};\dfrac{-2}{3}=\dfrac{-4}{6};\dfrac{-4}{-2}=\dfrac{6}{3};\dfrac{3}{-2}=\dfrac{6}{-4}\)
3: \(\left(-8\right)\cdot\left(-9\right)=4\cdot18\)
=>\(\dfrac{-8}{4}=\dfrac{18}{-9};\dfrac{-8}{18}=\dfrac{4}{-9};\dfrac{4}{-8}=\dfrac{-9}{18};\dfrac{18}{-8}=\dfrac{-9}{4}\)
7: \(a\cdot3,6=b\cdot1,2\)
=>\(\dfrac{a}{b}=\dfrac{1,2}{3,6};\dfrac{a}{1,2}=\dfrac{b}{3,6}\)
\(\dfrac{b}{a}=\dfrac{3.6}{1.2};\dfrac{1.2}{a}=\dfrac{3.6}{b}\)
8: \(5\cdot AM=6\cdot HK\)
=>\(\dfrac{AM}{HK}=\dfrac{6}{5};\dfrac{AM}{6}=\dfrac{HK}{5};\dfrac{HK}{AM}=\dfrac{5}{6};\dfrac{6}{AM}=\dfrac{5}{HK}\)
9: \(-2,5\cdot AB=5,5\cdot CD\)
=>\(\dfrac{AB}{CD}=\dfrac{5.5}{-2.5};\dfrac{AB}{5.5}=\dfrac{CD}{-2,5}\)
\(\dfrac{CD}{AB}=\dfrac{-2.5}{5.5};\dfrac{5.5}{AB}=\dfrac{-2.5}{CD}\)
10: \(AB\cdot CD=EF\cdot GH\)
=>\(\dfrac{AB}{EF}=\dfrac{GH}{CD};\dfrac{AB}{GH}=\dfrac{EF}{CD};\dfrac{EF}{AB}=\dfrac{CD}{GH};\dfrac{GH}{AB}=\dfrac{CD}{EF}\)
