Question

làm 2 dòng cuối bài 1 với ab dòng đầu bài 2 ạ

Answer 1

2:

a: =>2x-3=49

=>2x=52

=>x=26

b: =>|x-3|=5

=>x-3=5 hoặc x-3=-5

=>x=-2 hoặc x=8

1:

a: =10-3*5=10-15=-2

b: =4+5-1/3=9-1/3=26/3

c: =25/16*16/100-2/9*9/16+1

=1/4-1/8+1

=1/8+1=9/8

Answer 2

`@` `\text {Ans}`

`\downarrow`

`1,`

\(\sqrt{\dfrac{4}{9}}+\left(-\dfrac{1}{2}\right)^3-\left|-\dfrac{3}{7}\right|\cdot\dfrac{7}{8}\)

`= 2/3 - 1/8 - 3/7*7/8`

`= 2/3 - 1/8 - 3/8`

`= 2/3 - 1/2`

`= 4/6 - 3/6`

`= 1/6`

____

\(\left(\dfrac{3}{2}\right)^2-\left[\dfrac{1}{2}\div2-\sqrt{\left(-9\right)^2}\cdot\dfrac{1}{3}\right]\)

`= 9/4 - (1/2*1/2 - 9 * 1/3)`

`= 9/4 - (1/4 - 3)`

`= 9/4 - 1/4 + 3`

`= 2 + 3`

`= 5`

`2,`

`a)`

\(\sqrt{2x-3}=7\)

`=> 2x - 3 = 7^2`

`=> 2x - 3 = 49`

`=> 2x = 49 + 3`

`=> 2x = 52`

`=> x = 52 \div 2`

`=> x = 26`

Vậy, `x = 26`

`b)`

\(\sqrt{\left(x-3\right)^2}=5\)

`=> (x-3) = 5`

`=> x - 3 = 5`

`=> x = 5 + 3`

`=> x=8`

Vậy, `x=8.`

`\text {Kaizuu lv u.}`