\(\Leftrightarrow\left(4x+14\right)^2=\left(3x+9\right)^2\)
\(\Leftrightarrow\left(4x+14+3x+9\right)\cdot\left(4x+14-3x-9\right)=0\)
\(\Leftrightarrow\left(7x+23\right)\left(x+5\right)=0\)
hay \(x\in\left\{-\dfrac{23}{7};-5\right\}\)
\(\Leftrightarrow\left(8x+14\right)^2=\left(9x+3\right)^2\)
\(\Leftrightarrow8x+14=9x+3\)
\(\Leftrightarrow x=11\)