b: \(1\dfrac{1}{6}+\left(5\dfrac{1}{2}+1\dfrac{1}{3}\right)\cdot\dfrac{1}{2}\)
\(=\dfrac{7}{6}+\left(\dfrac{11}{2}+\dfrac{4}{3}\right)\cdot\dfrac{1}{2}\)
\(=\dfrac{7}{6}+\dfrac{41}{6}\cdot\dfrac{1}{2}\)
\(=\dfrac{14}{12}+\dfrac{41}{12}=\dfrac{55}{12}\)
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