Question

Ix-2I-4=1

 

Answer 1

\(\left|x-2\right|-4=1\\ =>\left|x-2\right|=1+4\\ =>\left|x-2\right|=5\\ TH1:x-2=5\left(x\ge2\right)\\ =>x=5+2=7\left(tm\right)\\ TH2:x-2=-5\left(x< 2\right)=>x=-5+2\\ =>x=-3\left(tm\right)\)

Vậy: ... 

Answer 2

\(\left|x-2\right|-4=1\\ \Rightarrow\left|x-2\right|=5\\ \Rightarrow\left[{}\begin{matrix}x-2=5\\x-2=-5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)

Vậy \(x\in\left\{7;-3\right\}\)