a, \(3\left(x+1\right)-5=2x+7\)
\(\Leftrightarrow3x+3-5=2x+7\Leftrightarrow x=9\)
b, \(x-2=6\left(x-1\right)+1\)
\(\Leftrightarrow x-2=6x-6+1\Leftrightarrow-5x=-3\Leftrightarrow x=\frac{3}{5}\)
a) 3( x + 1 ) - 5 = 2x + 7
<=> 3x + 3 - 5 = 2x + 7
<=> 3x - 2x = 7 - 3 + 5
<=> x = 9
b) x - 2 = 6( x - 1 ) + 1
<=> x - 2 = 6x - 6 + 1
<=> x - 6x = -6 + 1 + 2
<=> -5x = -3
<=> x = 3/5
\(a,3.\left(x+1\right)-5=2x+7\)
\(3x+3-5=2x+7\)
\(3x-2x=7+5-3\)
\(x=9\)
\(b,x-2=6.\left(x-1\right)+1\)
\(x-2=6x-6+1\)
\(x-6x=-5+2\)
\(-5x=-3\)
\(x=\frac{3}{5}\)
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