Ta có: \(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\)
PT: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
_____0,4______0,6_______________0,6 (mol)
\(\Rightarrow a=C_{M_{H_2SO_4}}=\dfrac{0,6}{0,5}=1,2\left(M\right)\)
\(V=V_{H_2}=0,6.24,79=14,874\left(l\right)\)