Question

Help!!!!!!!!!

Answer 1

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{y+z-x}{3+4-2}=\dfrac{x-y+z}{2-3+4}\)

\(\Rightarrow\dfrac{y+z-x}{5}=\dfrac{x-y+z}{3}\)

\(\Rightarrow A=\dfrac{y+z-x}{x-y+z}=\dfrac{5}{3}\)

Answer 2

Bạn tham khảo nhé:

* \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{y+z-x}{3+4-2}=\dfrac{y+z-x}{5}\)              (1)

* \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{x-y+z}{2-3+4}=\dfrac{x-y+z}{3}\)              (2)

(1)(2)=> \(\dfrac{y+z-x}{5}=\dfrac{x-y+z}{3}=\dfrac{y+z-x}{x-y+z}=\dfrac{5}{3}\)

         => A= \(\dfrac{5}{3}\)