Question

help :vvvv

Answer 1

cÓ: a+b+c=0

=>\(a^3+b^3+c^3=3abc\)

do đó: \(A=\frac{a^2}{bc}+\frac{b^2}{ac}+\frac{c^2}{ab}=\frac{a^3+b^3+c^3}{abc}=\frac{3abc}{abc}=3\)

Answer 2

A = 0