Question

Help mình với mn ơi

Answer 1

a: A=căn x-1

=>\(\left(\sqrt{x}-1\right)\cdot\dfrac{\sqrt{x}}{3}-\left(\sqrt{x}-1\right)=0\)

=>(căn x-1)(1/3*căn x-1)=0

=>x=1 hoặc x=9

b: \(B=\dfrac{x+2\sqrt{x}+4-x+\sqrt{x}-1}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}\)

\(=\dfrac{3\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}=\dfrac{3}{x-\sqrt{x}+1}\)

c: \(A\cdot B< =\dfrac{\sqrt{x}-1}{x-\sqrt{x}+1}\)

=>\(\dfrac{3\left(x-\sqrt{x}\right)}{3\left(x-\sqrt{x}+1\right)}< =\dfrac{\sqrt{x}-1}{x-\sqrt{x}+1}\)

=>x-2căn x+1<=0

=>(căn x-1)^2<=0

=>x=1