Question

Help me.I can not answer this question:

\(\left(x-\frac{1}{4}\right)^2=\frac{1}{9}\)

Please helpppppppppppppp meeeee!!!!

Answer 1

\(\left(x-\frac{1}{4}\right)^2=\frac{1}{9}\)

\(\left(x-\frac{1}{4}\right)^2=\left(\frac{1}{3}\right)^2\)

\(\Rightarrow\left|x-\frac{1}{4}\right|=\frac{1}{3}\)

\(x-\frac{1}{4}=\frac{1}{3}\)HOẶC   \(x-\frac{1}{4}=-\frac{1}{3}\)

\(x=\frac{7}{12}\)HOẶC   \(x=-\frac{1}{12}\)

Answer 2

Bùng nổ Saiya: giả vờ hay là ko bt thật thế?

Answer 3

Really, I can answer the question. 

\(\left(x-\frac{1}{4}\right)^2=\frac{1}{9}\)

\(\left(x-\frac{1}{4}\right)^2=\frac{1}{3}^2\)

\(=>x-\frac{1}{4}=\frac{1}{3}\)

\(x=\frac{1}{3}+\frac{1}{4}\)

\(x=\frac{7}{12}\)