Question

help me

Answer 1

Câu 2:

a: \(\Leftrightarrow4x^2+4x+1-4x^2-3x=2x-2\)

=>x+1=2x-2

=>-x=-3

hay x=3

b: \(\Leftrightarrow x\left(x^2-2x-24\right)=0\)

\(\Leftrightarrow x\left(x-6\right)\left(x+4\right)=0\)

hay \(x\in\left\{0;6;-4\right\}\)

c: \(\Leftrightarrow x^2-3x+2-3x-6=-x-10\)

\(\Leftrightarrow-6x-4=-x-10\)

=>-5x=-6

hay x=6/5(nhận)

Answer 2

Câu 2 : 

a, \(4x^2+4x+4-4x^2-3x=2x-2\Leftrightarrow x+4=2x-2\Leftrightarrow x=6\)

b, \(x\left(x^2-2x+1-25\right)=0\Leftrightarrow x\left(x-6\right)\left(x+4\right)=0\Leftrightarrow x=0;x=6;x=-4\)

c, đk : x khác 2 ; -2 \(\Rightarrow x^2-3x+2-3x-6=-x-10\)

\(\Leftrightarrow x^2-6x-4=-x-10\Leftrightarrow x^2-5x+6=0\Leftrightarrow\left(x-2\right)\left(x-3\right)=0\Leftrightarrow x=2\left(ktm\right);x=3\)