a: =>x-10/3=21/75=7/25
=>x=7/25+10/3=271/75
b: =>x+3/22=3/11
=>x=3/22
\(x-\dfrac{10}{3}=\dfrac{7}{15}.\dfrac{3}{5}=\dfrac{21}{75}\\ =>x=\dfrac{21}{75}+\dfrac{10}{3}=\dfrac{21+250}{75}=\dfrac{271}{75}\\ \\ x+\dfrac{3}{22}=\dfrac{27}{121}.\dfrac{11}{9}=\dfrac{9.3.11}{11.11.9}=\dfrac{3}{11}\\ =>x=\dfrac{3}{11}-\dfrac{3}{22}=\dfrac{6-3}{22}=\dfrac{3}{22}\\ \\ \dfrac{8}{23}.\dfrac{46}{24}-x=\dfrac{1}{3}\\ =>\dfrac{8.23.2}{23.8.3}-x=\dfrac{1}{3}\\ =>\dfrac{2}{3}-x=\dfrac{1}{3}\\ =>x=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
a) \(x-\dfrac{10}{3}=\dfrac{7}{15}.\dfrac{3}{5}\)
\(x-\dfrac{10}{3}=\dfrac{7}{25}\)
\(x=\dfrac{7}{25}+\dfrac{10}{3}\)
\(x=\dfrac{271}{75}\)
Vậy \(x=\dfrac{271}{75}\)
b) \(x+\dfrac{3}{22}=\dfrac{27}{121}.\dfrac{11}{9}\)
\(x+\dfrac{3}{22}=\dfrac{3}{11}\)
\(x=\dfrac{3}{11}-\dfrac{3}{22}\)
\(x=\dfrac{3}{22}\)
Vậy \(x=\dfrac{3}{22}\)
c) \(\dfrac{8}{23}.\dfrac{46}{24}-x=\dfrac{1}{3}\)
\(\dfrac{2}{3}-x=\dfrac{1}{3}\)
\(x=\dfrac{2}{3}-\dfrac{1}{3}\)
\(x=\dfrac{1}{3}\)
Vậy \(x=\dfrac{1}{3}\)
