vậy giúp câu này nhé mấy thánh hệ phương trình
\(\hept{\begin{cases}x+y=\sqrt[3]{2014}\\\left(\sqrt{x}+\sqrt{y}\right)\left(\frac{1}{\sqrt{x+3y}}+\frac{1}{\sqrt{y+3x}}\right)=2\end{cases}}\)
gpt: \(2\sqrt{3x+7}-5\sqrt[3]{x-6}=4\)
\(\left(x^2-3x+2\right)\left(x^2-12x+32\right)\le4x^2\)
\(\left(\sqrt{x+1}-1\right)\left(\sqrt{x^2-4x+7}+1\right)=x\)
gpt:
\(3\left(x^2-3x+1\right)+\sqrt{3\left(x^4+x^2+1\right)}=0\)
\(\sqrt[3]{x^3+5x^2}-1=\sqrt{\frac{5x^2-2}{6}}\)
gpt : \(x^2-4x+5-\frac{3x}{x^2+x+1}=\left(x-1\right)\left(1-\frac{2\sqrt{1-x}}{\sqrt{x^2+x+1}}\right)\)
Gpt: \(5x^2+3x+6=\left(7x+1\right)\sqrt{x^2+3}\)
GPT \(x^2+3x+1=\left(x+3\right)\sqrt{x^2+1}\)
Gpt: \(3x^2+x+1=\left(3x+1\right)\sqrt{x^2+1}\)
GPT: \(x^2-3x+3=\left(3x-\frac{4}{x}+1\right)\sqrt{x-1}\)
GPT: \(x^3+5x^2+2x=3\left(x+1\right)\sqrt{3x+2}.\)