\(\Rightarrow x^2+4x+4+x^3+9x^2+27x+27+x^4+16x^3+96x^2+256x+256=2\)
\(\Rightarrow x^4+17x^3+106x^2+287x+285=0\)
\(\Rightarrow\left(x+5\right)\left(x^2+9x+19\right)\left(x+3\right)=0\)
=> x + 5 = 0 => x = -5
hoặc x2 + 9x + 19 = 0 => x = \(\frac{-9+\sqrt{5}}{2}\); x = \(\frac{-9-\sqrt{5}}{2}\)
hoặc x + 3 = 0 => x = -3
Vậy pt có 4 nghiệm , k biết đúng k nữa , nếu sai thì giải cho tui nghen
GPT :\(\left(x+2\right)^2+\left(x+3\right)^3+\left(x+4\right)^4=2\)
gpt:
\(\sqrt{x}+\sqrt[4]{x\left(1-x\right)}+\sqrt[4]{\left(1-x\right)^3}=\sqrt{1-x}+\sqrt[4]{x^3}+\sqrt[4]{x^2\left(1-x\right)}\)
Gpt
a) \(\left(x-3\right)\left(x+1\right)+4\left(x-3\right)\sqrt{\frac{x+1}{x-3}}=-3\)
b)\(\frac{x\left(x^2+1\right)}{\left(x^2-x+1\right)}=2\)
Gpt \(x^2-4+4\left(x-2\right)\sqrt{\dfrac{x+2}{x-2}}=-3\)
GPT:\(\frac{\left(x+1\right)\left(x+28\right)\left(x+4\right)\left(x-10\right)\left(-5\right)}{\sqrt{x}\left(x-6\right)^{\frac{1}{2}}}\ln\left(x^2-10\right)=0\)
Nhân tài đâu giúp mình với mình tick cho
gpt: \(2\sqrt{3x+7}-5\sqrt[3]{x-6}=4\)
\(\left(x^2-3x+2\right)\left(x^2-12x+32\right)\le4x^2\)
\(\left(\sqrt{x+1}-1\right)\left(\sqrt{x^2-4x+7}+1\right)=x\)
GPT: \(\sqrt[3]{\left(65+x\right)^2}+4\sqrt[3]{\left(65-x\right)^2}=5\sqrt[3]{65^2-x^2}\)
\(0=-\frac{\left(x+2\right)^2+12}{\left(x+2\right)^2}+\frac{\left(x+1\right)^2+1}{\left(x+1\right)^2}-\frac{\left(x+3\right)^2+3}{\left(x+3\right)^2}+\frac{\left(x+4\right)^2+4}{\left(x+4\right)^2}\)
gpt:
\(3\left(x^2-3x+1\right)+\sqrt{3\left(x^4+x^2+1\right)}=0\)
\(\sqrt[3]{x^3+5x^2}-1=\sqrt{\frac{5x^2-2}{6}}\)
