\(\Leftrightarrow1-2\sin^2x+2\sin x-1=0\)
\(\Leftrightarrow-2\sin^2x+2\sin x=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\sin x=1\\\sin x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{2}+k2\pi\\x=k2\pi\end{matrix}\right.\left(k\in Z\right)\)