Question

  Giúppppp

Answer 1

ê bn cho mik bt tên bài ko mik cx đang cần giải bài này

:v

Answer 2

a: \(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot...\cdot\dfrac{2021}{2022}=\dfrac{1}{2022}\)

b: \(=\dfrac{2\left(\dfrac{1}{3}+\dfrac{1}{5}-\dfrac{1}{7}\right)}{11\left(\dfrac{1}{3}+\dfrac{1}{5}-\dfrac{1}{7}\right)}=\dfrac{2}{11}\)