Question

giúp

Answer 1

\(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2015}}{2014+\dfrac{2014}{2}+\dfrac{2013}{3}+\dfrac{2012}{4}+...+\dfrac{1}{2015}}\)

\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2015}}{\dfrac{2016}{2}+\dfrac{2016}{3}+...+\dfrac{2016}{2015}}\)

\(=\dfrac{1}{2016}\)