1)
\(\dfrac{13}{58}+\dfrac{5}{12}\)
\(=\dfrac{156}{696}+\dfrac{290}{696}\)
\(=\dfrac{223}{348}\)
2)
\(10-\dfrac{7}{12}\)
\(=\dfrac{10}{1}-\dfrac{7}{12}\)
\(=\dfrac{120}{12}-\dfrac{7}{12}\)
\(=\dfrac{113}{12}\)
3)
\(\dfrac{12}{17}:\dfrac{60}{51}\)
\(=\dfrac{12}{17}.\dfrac{51}{60}\)
\(=\dfrac{3}{5}\)
4)
\(\dfrac{3}{8}.\dfrac{5}{9}\)
\(=\dfrac{3.5}{8.9}\)
\(=\dfrac{5}{24}\)
a: \(=\dfrac{156+5\cdot58}{58\cdot12}=\dfrac{223}{348}\)
b: =120/12-7/12=113/12
c: \(=\dfrac{12}{17}\cdot\dfrac{51}{60}=\dfrac{12}{17}\cdot\dfrac{17}{20}=\dfrac{3}{5}\)
d: \(=\dfrac{15}{72}=\dfrac{5}{24}\)
\(\dfrac{13}{58}\) + \(\dfrac{5}{12}\) = \(\dfrac{78}{348}\) + \(\dfrac{30}{348}\) = \(\dfrac{108}{348}\) \(\dfrac{9}{29}\)
10 - \(\dfrac{7}{12}\) = \(\dfrac{120}{12}\) - \(\dfrac{7}{12}\) = \(\dfrac{113}{12}\)
\(\dfrac{12}{17}\) : \(\dfrac{60}{51}\) = \(\dfrac{12}{17}\) x \(\dfrac{51}{60}\) = \(\dfrac{12x17x3}{17x12x5}\) = \(\dfrac{3}{5}\)
\(\dfrac{3}{8}\) x \(\dfrac{5}{9}\) = \(\dfrac{3x5}{8x3x3}\) = \(\dfrac{5}{24}\)







