Question

Giúp với

Answer 1

a: \(=2\cdot3\sqrt{3}-3\cdot4\sqrt{3}+6\sqrt{3}\)

\(=0\)

b: \(=2\sqrt{3}-\sqrt{36}\)

\(=2\sqrt{3}-6\)

Answer 2

\(a,=6\sqrt{3}-12\sqrt{3}+6\sqrt{3}=2\sqrt{3}\\ b,=2\sqrt{3}-6\\ c,=\sqrt{2}-1-3+\sqrt{2}=2\sqrt{2}-4\\ d,=\dfrac{5\left(\sqrt{3}-\sqrt{2}\right)}{\sqrt{3}-\sqrt{2}}-\dfrac{2\left(\sqrt{3}+1\right)}{2}+\sqrt{3}=5-\sqrt{3}-1+\sqrt{3}=4\)