a: \(A=2\sqrt3-\sqrt{75}+2\cdot\sqrt{12}\)
\(=2\sqrt3-5\sqrt3+2\cdot2\sqrt3\)
\(=6\sqrt3-5\sqrt3=\sqrt3\)
b: \(B=\sqrt{\left(2-\sqrt5\right)^2}+\sqrt{\left(3-\sqrt5\right)^2}\)
\(=\left|2-\sqrt5\right|+\left|3-\sqrt5\right|\)
\(=\sqrt5-2+3-\sqrt5=-2+3=1\)
c: \(C=\left(\frac{x+2\sqrt{x}}{x-2\sqrt{x}}+\frac{\sqrt{x}}{\sqrt{x}-2}\right)\cdot\frac{1}{\sqrt{x}+1}\)
\(=\left(\frac{\sqrt{x}+2}{\sqrt{x}-2}+\frac{\sqrt{x}}{\sqrt{x}-2}\right)\cdot\frac{1}{\sqrt{x}+1}\)
\(=\frac{2\left(\sqrt{x}+1\right)}{\sqrt{x}-2}\cdot\frac{1}{\sqrt{x}+1}=\frac{2}{\sqrt{x}-2}\)









giúp mik với ạ chỉ cần rút gọn 6 cái biểu thức thui ạ .mong mn giúp đỡ.
