Question

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Answer 1

a: \(\left(x+\frac23\right)-\left(\frac12\right)^3=\left(-\frac13\right)^2\)

=>\(x+\frac23-\frac18=\frac19\)

=>\(x=\frac19-\frac23+\frac18=\frac19-\frac69+\frac18=\frac{-5}{9}+\frac18=\frac{-40+9}{72}=-\frac{31}{72}\)

b: \(\left|x-0,5\right|-\frac34=\frac23\)

=>\(\left|x-\frac12\right|=\frac34+\frac23=\frac{9+8}{12}=\frac{17}{12}\)

=>\(\left[\begin{array}{l}x-\frac12=\frac{17}{12}\\ x-\frac12=-\frac{17}{12}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{17}{12}+\frac12=\frac{23}{12}\\ x=-\frac{17}{12}+\frac12=\frac{-17}{12}+\frac{6}{12}=-\frac{11}{12}\end{array}\right.\)