\(C_1ntC_2ntC_3\\ \dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}=\dfrac{1}{C_{td}}\\ \Leftrightarrow\dfrac{1}{1}+\dfrac{1}{1,5}+\dfrac{1}{3}=\dfrac{1}{C_{td}}\\ \Rightarrow C_{td}=5.10^{-7}\left(F\right)\\ Q=Q_1=Q_2=Q_3=C_{td}U=5.10^{-7}.120=6.10^{-5}\left(C\right)\\ U_1=\dfrac{Q_1}{C_1}=\dfrac{6.10^{-5}}{10^{-6}}=60V\\ U_2=\dfrac{Q_2}{C_2}=\dfrac{6.10^{-5}}{1,5.10^{-6}}=40V\\ U_3=U-U_1-U_2=20V\)
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