\(x\left(3x-5\right)+\left(6x^5-4x^4+10x^3\right):\left(-2x^3\right)=1\\ =>3x^2-5x-3x^2+2x-5=1\\ =>-3x-5=1\\ =>-3x=1+5\\ =>-3x=6\\ =>x=6:\left(-3\right)\\ =>x=-2\)
Đúng 3
Bình luận (0)
ĐKXĐ: \(x\ne0\)
\(x\left(3x-5\right)+\left(6x^5-4x^4+10x^3\right):\left(-2x^3\right)=1\)
\(\Leftrightarrow3x^2-5x+\left(-2x^3\right).\left(-3x^2+2x-5\right):\left(-2x^3\right)=1\)
\(\Rightarrow3x^2-5x-3x^2+2x-5=1\)
\(\Leftrightarrow-3x=6\)
\(\Rightarrow x=-2\)
Đúng 2
Bình luận (0)
giúp mk vs ạ ai nhanh mk tick nha 
