Question

giúp mk nha

Answer 1

\(B=\dfrac{2x-5}{x-2}=\dfrac{2x-4-1}{x-2}=\dfrac{2\left(x-2\right)-1}{x-2}=2-\dfrac{1}{x-2}\)

Để \(B\in Z\Rightarrow\dfrac{1}{x-2}\in Z\)

\(\Rightarrow x-2=Ư\left(1\right)\)

\(\Rightarrow\left[{}\begin{matrix}x-2=-1\\x-2=1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)