Question

giúp mk nha

Answer 1

\(x\left(3x-5\right)+\left(6x^5-4x^4+10x^3\right):\left(-2x^3\right)=1\)

\(3x^2-5x-3x^2+2x-5=1\)

\(3x^2-3x^2-5x+2x-5=1\)

\(-3x-5=1\\ -3x=1+6\\ -3x=7\\ x=7:\left(-3\right)\\ x=-\dfrac{7}{3}\)

Answer 2

sua lai

\(3x^2-5x-3x^2+2x-5=1\\ 3x^2-3x^2-5x+2x-5=1\)

\(-3x-5=1\\ -3x=1+5\\ -3x=6\\ x=6:\left(-3\right)\\ x=-2\)