Question

Giúp mk cần 2,3

Answer 1

1: Thay x=25 vào A, ta được:

\(A=\dfrac{1}{1+5}=\dfrac{1}{6}\)

2: \(B=\dfrac{x-4\sqrt{x}+3-x+4-10+5\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}=\dfrac{\sqrt{x}-3}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}=\dfrac{1}{\sqrt{x}-2}\)