Question

Giúp mk ạ cần gấp ạ thanks các bạn chỉ cần làm bài 2,10 thôi ạ * Bài 2 ko cần làm a đâu ạ

Answer 1

Bài 2

\(a,2x+6=200-64\\ 2x+6=136\\ 2x=130\\ x=130:2\\ x=65\\ b,2\left(x-51\right)=16+20\\ 2\left(x-51\right)=36\\ x-51=18\\ x=69\\ c,\left[\left(6x-39\right):7\right]=12:4\\6x-39=3.7\\ 6x-39=21\\ 6x=60\\ x=10\)

Answer 2

2) 

a) \(200-\left(2x+6\right)=4^3\)

\(200-\left(2x+6\right)=64\)

\(2x+6=200-64\)

\(2x=136-6\)

\(2x=130\)

`=>x=130/2=65`

b) \(2\left(x-51\right)=2\cdot2^3+20\)

\(2\left(x-51\right)=2\cdot8+20\)

\(2\left(x-51\right)=36\)

\(x-51=18\)

\(x=18+51\)

`=>x=69`

c) \(\left[\left(6x-39\right):7\right]\cdot4=12\)

\(\left(6x-39\right):7=\dfrac{12}{4}=3\)

\(6x-39=21\)

\(6x=21+39=60\)

\(x=\dfrac{60}{6}\)

`=>x=10`

10)

\(Ư\left(13\right)=\left\{1;13\right\}\)    \(Ư\left(16\right)=\left\{1;2;4;8;16\right\}\)

\(Ư\left(0\right)=N\text{*}\)            \(Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)

b) 

\(B\left(9\right)=\left\{0;9;18;27;....\right\}\)    \(B\left(11\right)=\left\{0;11;22;33;...\right\}\)

\(B\left(15\right)=\left\{0;15;30;45;60;....\right\}\)   \(B\left(20\right)=\left\{0;20;40;60;...\right\}\)

 

Answer 3

2.b,2(x-51)=2.2³+20

=>2(x-51)=36

=>x-51=36:2

=>x-51=18

=>x=18+51

=>x=69

Vậy x=69

c,[(6x-39):7].4=12

=>[(6x-39):7]=12:4

=>[(6x-39):7=3

=>6x-39=3.7

=>6x-39=21

=>6x=21+39

=>6x=60

=>x=60:6

=>x=10

Vậy x=10

10.a,Ư(13)={1;13}

U(16)={1;2;4;8;16}

Ư(0)={1;2;3...}

Ư(18)={1;2;3;6;9;18}

b,B(9)={0;9;18;27;36...}

B(11)={0;11;22;33;44...}

B(15)={0;15;30;45;60...}

B(20)={0;20;40.60...}