Sửa đề: \(\frac{\left(x-2\right)^3}{8}=-\frac{27}{64}\cdot\frac35+\frac{-27}{64}\cdot\frac25\)
Ta có: \(\frac{\left(x-2\right)^3}{8}=-\frac{27}{64}\cdot\frac35+\frac{-27}{64}\cdot\frac25\)
=>\(\frac{\left(x-2\right)^3}{8}=-\frac{27}{64}\left(\frac35+\frac25\right)=-\frac{27}{64}=\left(-\frac34\right)^3\)
=>\(\frac{x-2}{2}=-\frac34\)
=>\(x-2=-\frac32\)
=>\(x=-\frac32+2=\frac12\)



