g: \(\Leftrightarrow\dfrac{2x+5}{95}+1+\dfrac{2x+6}{94}+1+\dfrac{2x+7}{93}+1=\dfrac{2x+93}{7}+1+\dfrac{2x+94}{6}+1+\dfrac{2x+95}{5}+1\)
=>2x+100=0
hay x=-50
e: \(\Leftrightarrow3\left(2x+1\right)=6\left(2x+1\right)+8\)
=>12x+6+8=6x+3
=>12x+14=6x+3
=>6x=-11
hay x=-11/6(nhận)
f: \(\Leftrightarrow\left(x-1\right)\left(x-2\right)\left(x-4\right)\left(x-5\right)=40\)
\(\Leftrightarrow\left(x^2-6x+5\right)\left(x^2-6x+8\right)=40\)
\(\Leftrightarrow\left(x^2-6x\right)^2+13\left(x^2-6x\right)=0\)
=>x(x-6)=0
=>x=0 hoặc x=6