4) Ta có: \(x^2\ge0\)
⇔ \(-x^2\le0\)
⇔ \(4-x^2\le4\)
⇔ \(\sqrt{4-x^2}\le2\)
Dấu = xảy ra khi \(x=2\)
Vậy GTLN của A là 2 khi x=2
5) Ta có: \(\sin^2\alpha+cos^2\alpha=1\)
⇒ \(cos^2\alpha=1-\dfrac{1}{4}\)
⇒ \(cos^2\alpha=\dfrac{3}{4}\)
⇒ \(\cos\alpha=\dfrac{\sqrt{3}}{2}\)
Ta có: \(\tan\alpha=\dfrac{sin\alpha}{cos\alpha}\)
\(tan\alpha=\dfrac{1}{2}:\dfrac{\sqrt{3}}{2}\)
\(tan\alpha=\dfrac{\sqrt{3}}{3}\)
Ta có: \(cot\alpha=\dfrac{1}{tan\alpha}\)
\(cot\alpha=\dfrac{3}{\sqrt{3}}\)
\(cot\alpha=\sqrt{3}\)