Question

Giúp bài 2 vs ạ mình cần gấp

Answer 1

\(2,\\ a,=6+12-15=3\\ b,=\left(2\sqrt{2}-3\sqrt{2}\right)\sqrt{2}=-\sqrt{2}\cdot\sqrt{2}=-2\\ c,=\dfrac{2\left(\sqrt{3}-1\right)}{2}-\dfrac{\sqrt{3}+2}{-1}+\dfrac{6\left(3-\sqrt{3}\right)}{6}\\ =\sqrt{3}-1+\sqrt{3}+2+3-\sqrt{3}=4+\sqrt{3}\)