(4-x)(2-x)=2(4-x)
8-4x-2x+x^2=8-2x
8-8-4x-2x+2x+x^2=0
-4x+x^2=0
x(-4+x)=0
\(\Rightarrow\hept{\begin{cases}x=0\\-4+x=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x=4\end{cases}}}\)
(4 - x)(2 - x) = 2.(4 - x)
2 - x = 2.(4 - x) : (4 - x)
2 - x = 2
x = 2 - 2
x = 0