Question

giúp mình với

Bài 5: Tìm x:

1; \((2x - 4)(2x - 3) - 4x(x - 1) = 0\)

2; \((6x - 4)(2x + 5) - 4x(3x + 7) = 0\)

Answer 1

1: \(\left(2x-4\right)\left(2x-3\right)-4x\left(x-1\right)=0\)

=>\(4x^2-6x-8x+12-4x^2+4x=0\)

=>-10x+12=0

=>-10x=-12

=>\(x=\frac{12}{10}=\frac65\)

2: \(\left(6x-4\right)\left(2x+5\right)-4x\left(3x+7\right)=0\)

=>\(12x^2+30x-8x-20-12x^2-28x=0\)

=>-6x-20=0

=>6x+20=0

=>6x=-20

=>\(x=-\frac{20}{6}=-\frac{10}{3}\)