a) \(x-\dfrac{3}{4}=\dfrac{1}{7}\)
\(x=\dfrac{1}{7}+\dfrac{3}{4}\)
\(x=\dfrac{25}{28}\)
b ) \(x-\dfrac{3}{10}=\dfrac{7}{15}\cdot\dfrac{3}{5}\)
\(x-\dfrac{3}{10}=\dfrac{21}{75}\)
\(x-\dfrac{3}{10}=\dfrac{7}{25}\)
\(x=\dfrac{7}{25}+\dfrac{3}{10}\)
\(x=\dfrac{29}{50}\)
a) x=25/28
b)x=29/50
chúc bạn học tốt ^^ !!!
\(a)\) \(x - \dfrac{3}{4} = \dfrac{1}{7}\)
\(x = \dfrac{3}{4} + \dfrac{1}{7}\)
\(x = \dfrac{21}{28} + \dfrac{4}{28} \)
\(x = \dfrac{25}{28} \)
Vậy \(x = \dfrac{25}{28} \)
\(b) \) \(x - \dfrac{3}{10} = \dfrac{7}{15} . \dfrac{3}{5} \)
\(x - \dfrac{3}{10} = \dfrac{7}{25}\)
\(x = \dfrac{7}{25} + \dfrac{3}{10} \)
\(x = \dfrac{14}{50} + \dfrac{15}{50} \)
\(x = \dfrac{29}{50} \)
Vậy \(x = \dfrac{29}{50} \)
a) x - \(\dfrac{3}{4}\)= \(\dfrac{1}{7}\) b) x - \(\dfrac{3}{10}\) = \(\dfrac{7}{15}\) .\(\dfrac{3}{5}\)
x = \(\dfrac{1}{7}\) + \(\dfrac{3}{4}\) x - \(\dfrac{3}{10}\) = \(\dfrac{7}{25}\)
x = \(\dfrac{25}{28}\) x = \(\dfrac{7}{25}\) + \(\dfrac{3}{10}\)
x = \(\dfrac{29}{50}\)
