Question

giúp mình với, cần gấp ạ

Answer 1

\(\dfrac{x^2+9}{x\left(x+3\right)}+\dfrac{6x}{x\left(x+3\right)}=\dfrac{x^2+6x+9}{x\left(x+3\right)}=\dfrac{\left(x+3\right)^2}{x\left(x+3\right)}=\dfrac{x+3}{x}\)

Answer 2

\(\dfrac{x^2+9}{x\left(x+3\right)}+\dfrac{6}{x+3}\\ =\dfrac{x^2+6x+9}{x\left(x+3\right)}\\ =\dfrac{\left(x+3\right)^2}{x\left(x+3\right)}\\=\dfrac{x+3}{x}\)