\(1,\dfrac{9}{17}.\dfrac{2}{7}+\dfrac{9}{17}.\dfrac{5}{7}=\dfrac{9}{17}\left(\dfrac{2}{7}+\dfrac{5}{7}\right)=\dfrac{9}{17}.1=\dfrac{9}{17}\)
\(2,\dfrac{-5}{9}.\dfrac{13}{28}-\dfrac{13}{28}.\dfrac{4}{9}=\dfrac{13}{28}\left(\dfrac{-5}{9}-\dfrac{4}{9}\right)=\dfrac{13}{28}.\left(-1\right)=\dfrac{-13}{28}\)
\(3,\dfrac{-1}{3}.\dfrac{1}{5}+\dfrac{1}{3}.\dfrac{1}{2}=\dfrac{1}{3}.\dfrac{-1}{5}+\dfrac{1}{3}.\dfrac{1}{2}=\dfrac{1}{3}\left(\dfrac{-1}{5}+\dfrac{1}{2}\right)=\dfrac{1}{3}.\dfrac{3}{10}=\dfrac{1}{10}\)