Question

giúp mình nha

Answer 1

2: \(B=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right)\cdot\dfrac{-2}{3}+\dfrac{1}{3}-\left(-\dfrac{1}{6}\right):\left(-2\right)\)

\(=\dfrac{-11}{10}\cdot\dfrac{-2}{3}+\dfrac{1}{3}-\dfrac{1}{6}\cdot\dfrac{2}{1}\)

\(=\dfrac{-22}{30}=\dfrac{-11}{15}\)