Bài 1:
a: \(A=\dfrac{4}{7}+\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{3}{4}+\dfrac{5}{4}=1+2=3\)
b: \(B=\left(-\dfrac{1}{3}-\dfrac{2}{3}\right)+\left(\dfrac{2}{5}+\dfrac{1}{5}-\dfrac{3}{5}\right)=-1\)
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