Question

Giúp mình làm với ạ 🥺

Answer 1

\(1,\\ a,=4-5y\\ b,=\dfrac{20x}{3y}\cdot\dfrac{6y}{4}=\dfrac{10x}{1}=10x\\ 2,\\ a,=\left(2x+2-4\right)\left(2x+2+4\right)=2\left(x+1-2\right)2\left(x+1+2\right)\\ =4\left(x-1\right)\left(x+3\right)\\ b,=\left(2xy-xz\right)+\left(6y-3z\right)\\ =2x\left(y-z\right)+3\left(y-z\right)=\left(2x+3\right)\left(y-z\right)\)