Question

Giúp mình làm câu 1, câu 2 đang gấp

Answer 1

Bài 1:

\(=\dfrac{2\left(x-2\right)-\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x-6}{x^2-4}\)

Bài 2:

\(=\dfrac{\left(x-3\right)^2}{x-2}.\dfrac{2\left(x^2-4\right)}{2\left(x-3\right)}=\dfrac{\left(x-3\right)\left(x-2\right)\left(x+2\right)}{x-2}=\left(x-3\right)\left(x+2\right)=x^2-x-6\)