Bài 1:
\(a,\dfrac{-3}{5}+\dfrac{11}{10}=\dfrac{-6}{10}+\dfrac{11}{10}=\dfrac{5}{10}=\dfrac{1}{2}\\ b,\dfrac{-6}{20}+\dfrac{-11}{22}=\dfrac{-3}{10}-\dfrac{1}{2}=\dfrac{-3}{10}-\dfrac{5}{10}=\dfrac{-8}{10}=\dfrac{-4}{5}\\ c,\dfrac{7}{14}-\dfrac{-3}{6}=\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{2}{2}=1\\ d,5-\dfrac{-2}{3}=\dfrac{15}{3}+\dfrac{2}{3}=\dfrac{17}{3}\\ e,-11+\dfrac{3}{7}=\dfrac{-77}{7}+\dfrac{3}{7}=\dfrac{-74}{7}\\ g,-6-\dfrac{7}{25}=\dfrac{-150}{25}-\dfrac{7}{25}=\dfrac{-157}{25}\)
Bài 2:
\(A=\dfrac{-11}{2022}+\dfrac{19}{1999}+\dfrac{11}{2022}+\dfrac{18}{1999}\)
\(\Rightarrow A=\left(\dfrac{-11}{2022}+\dfrac{11}{2022}\right)+\left(\dfrac{19}{1999}+\dfrac{18}{1999}\right)\)
\(\Rightarrow A=0+\dfrac{37}{1999}\)
\(\Rightarrow A=\dfrac{37}{1999}\)
