Bài 5:
a: \(M=\dfrac{1+a}{\sqrt{a}\left(\sqrt{a}-1\right)}\cdot\dfrac{a-1}{\sqrt{a}+1}=\dfrac{a+1}{\sqrt{a}}\)
b: \(M-2=\dfrac{a+1-2\sqrt{a}}{\sqrt{a}}=\dfrac{\left(\sqrt{a}-1\right)^2}{\sqrt{a}}>0\)
=>M>2
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