\(=\left(\dfrac{3-2\sqrt{2}}{3+2\sqrt{2}}+\dfrac{3-2\sqrt{2}}{3+2\sqrt{2}}\right)\cdot\dfrac{\sqrt{4-2\sqrt{3}}}{\sqrt{2}\left(\sqrt{3}-1\right)}\)
\(=\dfrac{9-8+9-8}{1}\cdot\dfrac{1}{\sqrt{2}}=\dfrac{2}{\sqrt{2}}=\sqrt{2}\)
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